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(C) Colorblindness is an $X$-linked recessive trait. Let $X^c$ represent the allele for colorblindness and $X$ represent the normal allele.$1$. The ma

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Half of the sons will be colorblind.

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(C) Colorblindness is an $X$-linked recessive trait. Let $X^c$ represent the allele for colorblindness and $X$ represent the normal allele.$1$. The man is colorblind, so his genotype is $X^c Y$.$2$. The woman is the daughter of a colorblind father, meaning she inherited an $X^c$ chromosome from her father. Since she is not stated to be colorblind, she must be a carrier, with genotype $X^c X$.$3$. The cross is $X^c Y 	imes X^c X$.$4$. The possible genotypes of the offspring are:- $X^c X^c$ (Colorblind daughter)- $X^c X$ (Carrier daughter)- $X^c Y$ (Colorblind son)- $XY$ (Normal son)$5$. From the results, $50\%$ of the sons are colorblind and $50\%$ of the daughters are colorblind. However, looking at the options provided, the question asks for the outcome. Since $50\%$ of sons are colorblind, option $C$ is the correct description of the inheritance pattern.

$A$ colorblind man marries a woman who is the daughter of a colorblind father. What will be the status of their offspring regarding colorblindness?

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