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Question

(D) The force acting on a charged particle moving with velocity $\vec{v}$ in a magnetic field $\vec{B}$ is given by the Lorentz force formula:$\vec{F}

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angle between can have any value other than zero and $180^{\circ}$

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(D) The force acting on a charged particle moving with velocity $\vec{v}$ in a magnetic field $\vec{B}$ is given by the Lorentz force formula:$\vec{F} = q(\vec{v} 	imes \vec{B})$The magnitude of this force is given by:$F = qvB \sin 	heta$where $	heta$ is the angle between the velocity vector $\vec{v}$ and the magnetic field vector $\vec{B}$.For the force to be non-zero $(F 
eq 0)$,we must have $\sin 	heta 
eq 0$.Since $\sin 	heta = 0$ at $	heta = 0^{\circ}$ and $	heta = 180^{\circ}$,the force is zero in these cases.Therefore,for the force to be non-zero,the angle $	heta$ can have any value other than $0^{\circ}$ and $180^{\circ}$.

When a charged particle moving with velocity $\vec{v}$ is subjected to a magnetic field of induction $\vec{B}$,the force on it is non-zero. This implies that

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