When a capillary tube is dipped vertically in water,the rise of water in the capillary is $h$. The angle of contact is $0^{\circ}$. Now,the tube is depressed so that its length above the water surface is $\frac{h}{3}$. The new apparent angle of contact is $(\cos 0^{\circ} = 1)$.

Water rises up to $10 \, cm$ height in a long capillary tube. If this tube is immersed in water so that the height above the water surface is only $8 \, cm$,then:

The following observations were taken for determining surface tension $T$ of water by the capillary method:
Diameter of capillary,$D = 1.25 \times 10^{-2} \; m$
Rise of water,$h = 1.45 \times 10^{-2} \; m$
Using $g = 9.80 \; m/s^2$ and the simplified relation $T = \frac{rhg}{2} \times 10^3 \; N/m$,the possible error in surface tension is ........... $\%$. (Assume the least count of the measuring instrument is $0.01 \times 10^{-2} \; m$)

The water rises in the capillary to a height of $10\, cm$. If the surface tension of water is $73 \times 10^{-3}\, N/m$,density is $10^3\, kg/m^3$ and $g = 9.8\, m/s^2$,then find the radius of the capillary. (in $, cm$)

Water rises in a vertical capillary tube up to a height of $2.0\ cm$. If the tube is inclined at an angle of $60^o$ with the vertical,then up to what length will the water rise in the tube? (in $cm$)

Identify the correct figure which shows the relation between the height of water column in a capillary tube and the capillary radius.