Water rises up to 10 , cm height in a long ca | vedclass

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(B) The height to which water rises in a capillary tube is given by $h = \frac{2T \cos 	heta}{ho r g}$. Given that the capillary rise is $10 \, cm$

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Water rises up to the upper end and forms a spherical surface

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(B) The height to which water rises in a capillary tube is given by $h = \frac{2T \cos 	heta}{ho r g}$. Given that the capillary rise is $10 \, cm$,the water column will naturally try to reach this height. If the tube is cut or immersed such that the length above the water surface is less than the equilibrium height $(8 \, cm < 10 \, cm)$,the water will rise to the top of the tube. To maintain equilibrium,the radius of curvature of the meniscus will adjust such that $h' = \frac{2T \cos 	heta'}{ho r' g} = 8 \, cm$. Thus,the water will rise to the upper end and form a spherical surface with a different radius of curvature to satisfy the pressure balance.

Water rises up to $10 \, cm$ height in a long capillary tube. If this tube is immersed in water so that the height above the water surface is only $8 \, cm$,then:

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