Water rises in a vertical capillary tube up to a height of $2.0\ cm$. If the tube is inclined at an angle of $60^o$ with the vertical,then up to what length will the water rise in the tube? (in $cm$)

The radius of the bore of a capillary tube is $r$ and the angle of contact of the liquid is $\theta$. When the tube is dipped in the liquid,the radius of curvature of the meniscus of liquid rising in the tube is

The lower end of a capillary tube is dipped into water and it is observed that the water in the capillary tube rises by $7.5 \ cm$. Find the radius of the capillary tube used,if the surface tension of water is $7.5 \times 10^{-2} \ N \ m^{-1}$. The angle of contact between water and glass is $0^{\circ}$ and the acceleration due to gravity is $10 \ m \ s^{-2}$.

When one end of a capillary tube is dipped in water,the height of the water column is $h$. The upward force of $108 \ dyne$ due to surface tension is balanced by the force due to the weight of the water column. What is the inner circumference of the capillary (in $cm$)? (Surface tension of water $T = 7.2 \times 10^{-2} \ N/m$)

If the surface tension of water is $0.06 \, N/m$,then the capillary rise in a tube of diameter $1 \, mm$ is ....... $cm$ (assume $\theta = 0^\circ$,$g = 10 \, m/s^2$,and density of water $\rho = 1000 \, kg/m^3$).

$A$ capillary tube of radius $R$ is immersed in water and water rises in it to a height $H$. The mass of water in the capillary tube is $M$. If the radius of the tube is halved,the mass of water that will rise in the capillary tube will now be