The Wheatstone bridge principle is used to measure the specific resistance $(S_1)$ of a given wire,having length $L$ and radius $r$. If $X$ is the resistance of the wire,then the specific resistance is: $S_1 = X \left( \frac{\pi r^2}{L} \right)$. If the length of the wire is doubled,then the value of the specific resistance will be:
- A$\frac{S_1}{4}$
- B$2 S_1$
- C$\frac{S_1}{2}$
- D$S_1$
Explore More
Similar Questions
The value of unknown resistance $(x)$ for which the potential difference between $B$ and $D$ will be zero in the arrangement shown,is: (in $Omega$)
DifficultJEE MAIN 2024
View SolutionThe value of current $I$ in the given circuit is (in $A$)
Why is the circuit configuration known as a Wheatstone bridge?
Medium
View SolutionThe internal resistances of two cells shown are $0.1\,\Omega$ and $0.3\,\Omega$. If $R = 0.2\,\Omega$,the potential difference across the cell
Medium
View SolutionThe figure shows a network of five resistances and two batteries. The current through the $15\,V$ battery is .............. $A$.
Difficult
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo