The value of current I in the given circuit i | vedclass

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(D) According to Kirchhoff's Current Law $(KCL)$,the sum of currents entering a junction must equal the sum of currents leaving the junction.
Let

Vedclass · Accepted Answer

$28$

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(D) According to Kirchhoff's Current Law $(KCL)$,the sum of currents entering a junction must equal the sum of currents leaving the junction.
Let the four junctions be $J_1$ (top-left),$J_2$ (top-right),$J_3$ (bottom-left),and $J_4$ (bottom-right).
At junction $J_1$: $20 \ A$ enters,$15 \ A$ leaves downwards,and $x \ A$ leaves towards the right. So,$20 = 15 + x \implies x = 5 \ A$.
At junction $J_3$: $15 \ A$ enters from above and $5 \ A$ enters from the bottom-left. The total current $15 + 5 = 20 \ A$ leaves towards the right.
At junction $J_2$: $5 \ A$ enters from the left and $3 \ A$ enters from the top-right. The total current $5 + 3 = 8 \ A$ leaves downwards.
At junction $J_4$: $20 \ A$ enters from the left and $8 \ A$ enters from above. The total current $I = 20 + 8 = 28 \ A$ leaves through the branch $I$.
Thus,the value of current $I$ is $28 \ A$.

The value of current $I$ in the given circuit is (in $A$)

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