Wheat stone bridge is balanced. Find ratio of | vedclass

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Question

$\frac{	ext { Power in }(\mathrm{P}+\mathrm{Q})}{	ext { Power in }(\mathrm{R}+\mathrm{S})}=\frac{\frac{\mathrm{V}^{2}}{\mathrm{P}+\mathrm{Q}}}{\frac

Vedclass · Accepted Answer

$R : P$

Vedclass · Answer

$\frac{	ext { Power in }(\mathrm{P}+\mathrm{Q})}{	ext { Power in }(\mathrm{R}+\mathrm{S})}=\frac{\frac{\mathrm{V}^{2}}{\mathrm{P}+\mathrm{Q}}}{\frac{\mathrm{V}^{2}}{\mathrm{R}+\mathrm{S}}}=\frac{\mathrm{R}+\mathrm{S}}{\mathrm{P}+\mathrm{Q}}$

$=\frac{\mathrm{R}\left[1+\frac{\mathrm{S}}{\mathrm{R}}ight]}{\mathrm{P}\left[1+\frac{\mathrm{Q}}{\mathrm{P}}ight]}$       ........$(A)$

Also $\frac{\mathrm{P}}{\mathrm{R}}=\frac{\mathrm{Q}}{\mathrm{S}} \Rightarrow \frac{\mathrm{S}}{\mathrm{R}}=\frac{\mathrm{Q}}{\mathrm{P}}$            ...........$(B)$

from  $(A)$ and $(B)$

$\frac{	ext { Power in }(\mathrm{P}+\mathrm{Q})}{	ext { Power in }(\mathrm{R}+\mathrm{J})}=\frac{\mathrm{R}}{\mathrm{P}}$

Wheat stone bridge is balanced. Find ratio of electric power dissipated in $(P + Q)$ to $(R + S)$

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