Two resistors of resistance 100,Omega and 200 | vedclass

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(A) Since both resistors are connected in parallel,the potential difference $(V)$ across both resistors is the same.Thermal energy $(H)$ developed in

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$2: 1$

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(A) Since both resistors are connected in parallel,the potential difference $(V)$ across both resistors is the same.Thermal energy $(H)$ developed in a resistor is given by $H = \frac{V^2}{R} 	imes t$.For a given time $(t)$ and constant potential difference $(V)$,the thermal energy is inversely proportional to the resistance: $H \propto \frac{1}{R}$.Therefore,the ratio of thermal energy in $100\,\Omega$ $(H_1)$ to that in $200\,\Omega$ $(H_2)$ is:$\frac{H_1}{H_2} = \frac{R_2}{R_1} = \frac{200\,\Omega}{100\,\Omega} = \frac{2}{1}$.Thus,the ratio is $2: 1$.

Two resistors of resistance $100\,\Omega$ and $200\,\Omega$ are connected in parallel in an electrical circuit. The ratio of the thermal energy developed in $100\,\Omega$ to that in $200\,\Omega$ in a given time is:

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