For a given surface,the Gauss's law is stated as $\oint {E \cdot ds} = 0$. From this,we can conclude that:

Two point charges $2q$ and $q$ are placed at vertex $A$ and the centre of face $CDEF$ of the cube,respectively,as shown in the figure. The electric flux passing through the cube is:

If electric flux is coming out of a Gaussian surface,what is associated with the surface?

If charge $q$ is placed on one of the vertex of a cube,then total electric flux passing through the cube is . . . . . . .

$A$ long straight wire of radius $1 \, mm$ has a uniform charge distribution. The charge per $cm$ length of the wire is $Q \, Coulombs$. $A$ cylinder of radius $50 \, cm$ and length $1 \, m$ encloses the wire symmetrically. The total flux passing through the surface of the cylinder is ..........

$A$ charged particle $q$ is placed at the centre $O$ of a cube of side length $L$ $(A, B, C, D, E, F, G, H)$. Another identical charge $q$ is placed at a distance $L$ from $O$, outside the cube, as shown in the figure. The electric flux through the face $BGFC$ is