What role does the molecular interaction play in a solution of alcohol and water?

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) Alcohol and water both have a strong tendency to form intermolecular hydrogen bonding. On mixing the two,a solution is formed as a result of the formation of $H$-bonds between alcohol and $H_2O$ molecules. However,these interactions are weaker and less extensive than those in pure $H_2O$. Thus,they show a positive deviation from ideal behavior. As a result of this,the solution of alcohol and water will have a higher vapour pressure and a lower boiling point than that of pure water and pure alcohol.

Explore More

Similar Questions

When ethanol is mixed with acetone,what happens to the heat?

Benzene and toluene form an ideal solution. If the partial vapor pressures of benzene and toluene are $1.55 \ kPa$ and $1.85 \ kPa$ respectively,what is the mole ratio of benzene to toluene in the solution?

Identify the mixture that shows positive deviations from Raoult's Law.

Benzene and toluene form nearly ideal solutions. At $20\,^{\circ}C$,the vapour pressure of benzene is $75\,torr$ and that of toluene is $22\,torr$. The partial vapour pressure of benzene at $20\,^{\circ}C$ for a solution containing $78\,g$ of benzene and $46\,g$ of toluene in $torr$ is

$A$ liquid mixture contains $10 \ moles$ of $A$ $(P_A^0 = 200 \ mm \ Hg)$ and $10 \ moles$ of $B$ $(P_B^0 = 100 \ mm \ Hg)$. The vapour pressure over the liquid mixture is $160 \ mm \ Hg$. Which statement is correct?

Difficult
View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo