Neutrino is a particle, which is

If $_{92}{U^{238}}$ undergoes successively $8 \alpha$- decays and $6 \beta$- decays, then resulting nucleus is

During a negative beta decay

A nuclear decay is possible if the mass of the parent nucleus exceeds the total mass of the decay particles. If $M(A, Z)$ denotes the mass of a single neutral atom of an element with mass number $A$ and atomic number $Z$, then the minimal condition that the $\beta$ decay $X_Z^A \rightarrow Y_{Z+1}^A+\beta^{-}+\bar{v}_e$ will occur is ( $m_e$ denotes the mass of the $\beta$ particle and the neutrino mass $m_v$ can be neglected)

$^{22}Ne$ nucleus after absorbing energy decays into two $\alpha - $ particles and an unknown nucleus. The unknown nucleus is

Assertion : Radioactive nuclei emit ${\beta ^ - }$ particles.

Reason : Electrons exist inside the nucleus