What is the maximum voltage of $220\, V$ (in $, V$)?

The alternating voltage is given by $v=v_0 \sin \left(\omega t+\frac{\pi}{3}\right)$. When will the voltage be maximum for the first time?

An alternating current is given by $I = I_A \sin \omega t + I_B \cos \omega t$. The r.m.s. current will be

In an $A.C.$ circuit,$I_{\text{rms}}$ and $I_{0}$ are related as:

Match the following:
Currents $r.m.s.$ values
$(1) x_0 \sin \omega t$ $(i) x_0$
$(2) x_0 \sin \omega t \cos \omega t$ $(ii) \frac{x_0}{\sqrt{2}}$
$(3) x_0 \sin \omega t + x_0 \cos \omega t$ $(iii) \frac{x_0}{2\sqrt{2}}$

Find the $RMS$ value for the saw-tooth voltage of peak value $V_0$ from $t = 0$ to $t = 2T$ as shown in the figure.