Find the rms value for the saw-tooth voltage | vedclass

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Question

general equation of $\mathrm{V}$

$\mathrm{V}=\frac{\mathrm{V}_{0}}{\mathrm{T} / 2} \mathrm{t}-\mathrm{V}_{0}=\frac{2 \mathrm{V}_{0}}{\mathrm{T}} \m

Vedclass · Accepted Answer

$\frac{V_0}{\sqrt{3} }$

Vedclass · Answer

general equation of $\mathrm{V}$

$\mathrm{V}=\frac{\mathrm{V}_{0}}{\mathrm{T} / 2} \mathrm{t}-\mathrm{V}_{0}=\frac{2 \mathrm{V}_{0}}{\mathrm{T}} \mathrm{t}-\mathrm{V}_{0}$

${V_{rms}} = {\left[ {\frac{{\int_0^T {{V^2}} dt}}{T}} \right]^{\frac{1}{2}}} = {\left[ {\frac{{\int_0^T {{{\left( {\frac{{2{V_0}}}{T}t - {V_0}} \right)}^2}} dt}}{T}} \right]^{\frac{1}{2}}} = \frac{{{V_0}}}{{\sqrt 3 }}$

Find the rms value for the saw-tooth voltage of peak value $V_0$ from $t = 0$ to $t = 2T$ as shown in figure

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