What is the correct order of spin only magnet | vedclass

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Question

(C) Spin only magnetic moments depend upon the number of unpaired electrons; more the number of unpaired electrons,greater will be the spin only magne

Vedclass · Accepted Answer

$Mn^{2+} > Cr^{2+} > V^{2+}$

Vedclass · Answer

(C) Spin only magnetic moments depend upon the number of unpaired electrons; more the number of unpaired electrons,greater will be the spin only magnetic moment.For $Mn$ $(Z=25)$: $[Ar] 3d^5 4s^2$. Thus,$Mn^{2+} = [Ar] 3d^5$. Number of unpaired electrons = $5$.For $Cr$ $(Z=24)$: $[Ar] 3d^5 4s^1$. Thus,$Cr^{2+} = [Ar] 3d^4$. Number of unpaired electrons = $4$.For $V$ $(Z=23)$: $[Ar] 3d^3 4s^2$. Thus,$V^{2+} = [Ar] 3d^3$. Number of unpaired electrons = $3$.Since the magnetic moment $\mu = \sqrt{n(n+2)} \ BM$,where $n$ is the number of unpaired electrons,the order is $Mn^{2+} (5) > Cr^{2+} (4) > V^{2+} (3)$.

What is the correct order of spin only magnetic moment (in $BM$) of $Mn^{2+}, Cr^{2+}$ and $V^{2+}$?

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