If $\overrightarrow{a} \cdot \hat{i} = \overrightarrow{a} \cdot (2 \hat{i} + \hat{j}) = \overrightarrow{a} \cdot (\hat{i} + \hat{j} + 3 \hat{k}) = 1$,then $\overrightarrow{a}$ is equal to :

  • A
    $\hat{i} - \hat{k}$
  • B
    $\frac{1}{3}(3 \hat{i} + 3 \hat{j} + \hat{k})$
  • C
    $\frac{1}{3}(\hat{i} + \hat{j} + \hat{k})$
  • D
    $\frac{1}{3}(3 \hat{i} - 3 \hat{j} + \hat{k})$

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