What is [H^{+}] in mol/L of a solution that i | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The solution contains a weak acid $(CH_3COOH)$ and its conjugate salt $(CH_3COONa)$,which forms an acidic buffer.For an acidic buffer,the concentr

Vedclass · Accepted Answer

$9.0 	imes 10^{-6}$

Vedclass · Answer

(D) The solution contains a weak acid $(CH_3COOH)$ and its conjugate salt $(CH_3COONa)$,which forms an acidic buffer.For an acidic buffer,the concentration of $[H^{+}]$ is given by the Henderson-Hasselbalch equation:$[H^{+}] = K_a 	imes \frac{[acid]}{[salt]}$Given:$K_a = 1.8 	imes 10^{-5}$$[acid] = [CH_3COOH] = 0.10\, M$$[salt] = [CH_3COONa] = 0.20\, M$Substituting the values:$[H^{+}] = 1.8 	imes 10^{-5} 	imes \frac{0.10}{0.20}$$[H^{+}] = 1.8 	imes 10^{-5} 	imes 0.5$$[H^{+}] = 0.9 	imes 10^{-5} = 9.0 	imes 10^{-6}\, mol/L$

What is $[H^{+}]$ in $mol/L$ of a solution that is $0.20\, M$ in $CH_3COONa$ and $0.10\, M$ in $CH_3COOH$? $K_a$ for $CH_3COOH = 1.8 \times 10^{-5}$.

Similar Questions

To obtain a buffer which should be suitable for maintaining a $pH$ of about $4 - 5$,we need to have in solution,a mixture of

Calculate the $pH$ of a buffer solution containing $0.35 \ M$ weak acid and $0.70 \ M$ of its salt with a strong base if $pK_{a}$ is $4.56$.

The constant acidity and basicity of a buffer solution is due to........

The approximate $pH$ of a solution formed by mixing equal volumes of $0.1 \ M$ sodium propanoate and $0.1 \ M$ propanoic acid (if the dissociation constant of propanoic acid is $1.3 \times 10^{-5}$) will be:

Which of the following mixtures will produce a buffer solution with $pH = 9$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module