What are X and Y in the following reaction? H | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Reductive ozonolysis of $Hex-2-ene$ $(CH_3-CH_2-CH_2-CH=CH-CH_3)$ involves the addition of ozone across the double bond followed by cleavage with

Vedclass · Accepted Answer

$X = CH_3-CH_2-CH_2-CHO, Y = CH_3-CHO$

Vedclass · Answer

(C) Reductive ozonolysis of $Hex-2-ene$ $(CH_3-CH_2-CH_2-CH=CH-CH_3)$ involves the addition of ozone across the double bond followed by cleavage with $Zn/H_2O$ to produce two carbonyl compounds.Cleavage of the $C=C$ bond in $Hex-2-ene$ occurs at the $2^{nd}$ position.The reaction is: $CH_3-CH_2-CH_2-CH=CH-CH_3 \xrightarrow{O_3, Zn/H_2O} CH_3-CH_2-CH_2-CHO + CH_3-CHO$.Thus,$X = CH_3-CH_2-CH_2-CHO$ $(Butanal)$ and $Y = CH_3-CHO$ $(Ethanal)$.

What are $X$ and $Y$ in the following reaction? $Hex-2-ene$ $\xrightarrow{O_3} \text{Ozonide}$ $\xrightarrow{Zn + H_2O} X + Y$

Similar Questions

Assertion : $1$-Butene on reaction with $HBr$ in the presence of a peroxide produces $1$-bromobutane.
Reason : It involves the free radical mechanism.

Which of the following compounds does not evolve $CO_2$ gas when it undergoes oxidative ozonolysis?

Conc. $H_2SO_4$ reacts with $C_2H_5OH$ at $170\,^{\circ}C$ to form

What is the product formed by the reaction of propene with $Br_2$ in $CCl_4$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module