Given below are two statements.Statement I : | vedclass

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(D) Statement $I$ is incorrect. Alkenes are generally considered more reactive than alkanes due to the presence of the $\pi$-bond,but the stability of

Vedclass · Accepted Answer

Statement $I$ is incorrect but Statement $II$ is correct.

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(D) Statement $I$ is incorrect. Alkenes are generally considered more reactive than alkanes due to the presence of the $\pi$-bond,but the stability of a molecule depends on its total bond energy. Alkenes are not inherently 'less stable' than alkanes in a way that makes them unstable compounds; they are simply more reactive towards electrophilic addition.Statement $II$ is correct. $A$ carbon-carbon double bond $(C=C)$ consists of one $\sigma$-bond and one $\pi$-bond. The total bond energy of a $C=C$ bond (approx. $610 \ kJ/mol$) is significantly higher than that of a $C-C$ single bond (approx. $348 \ kJ/mol$). Therefore,the strength of the double bond is greater than that of the single bond.

Similar Questions

The reaction of $3$-phenylpropene with $HBr$ gives (as the major product):

The correct order of rates of addition of $Br_2/\text{water}$ to the following alkenes is:
[$A$] $CH_2=CH_2$
[$B$] $CH_2=CH-NO_2$
[$C$] $CH_3-CH_2-CH=CH_2$
[$D$] $CH_3-CH=CH_2$

$CH_2 = CH_2 + B_2H_6 \xrightarrow[H_2O_2]{NaOH} \text{Product}$.
The product in the above reaction is:

The order of increasing reactivity towards $HCl$ of the following compounds will be:
$(1)$ $CH_2 = CH_2$
$(2)$ $(CH_3)_2C = CH_2$
$(3)$ $CH_3CH = CHCH_3$

What is the product formed when $RCH = CH_2$ is treated with $B_2H_6$ followed by oxidation with alkaline $H_2O_2$?

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