What is the product formed by the reaction of propene with $Br_2$ in $CCl_4$?

For the given reaction:
(Cyclohexyl)-$CH$=$CH$-(Cyclohexyl) $\xrightarrow{KMnO_4/H^+}$ '$P$' (major product)
'$P$' is:

In the presence of peroxide,$HCl$ and $HI$ do not give anti-Markownikoff's addition to alkenes because

Addition of $HI$ on the double bond of propene yields isopropyl iodide and not $n$-propyl iodide as the major product. This is because the addition proceeds through

The reaction of $HBr$ with the following compound would produce:

Taking into account the stability of various cycloalkanes and carbocations,as well as the rules governing mechanisms of carbocation rearrangements,what is the most likely product of this reaction?