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(D) The upward force due to surface tension is given by $F = T 	imes L$,where $L$ is the circumference of the capillary $(L = 2 \pi r)$.Given that th

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$6.25 	imes 10^{-2} \ m$

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(D) The upward force due to surface tension is given by $F = T 	imes L$,where $L$ is the circumference of the capillary $(L = 2 \pi r)$.Given that the upward force balances the weight of the water,we have:$T 	imes (2 \pi r) = 	ext{Weight of water}$$T 	imes L = 75 	imes 10^{-4} \ N$Substituting the given value of surface tension $T = 12 	imes 10^{-2} \ N/m$:$(12 	imes 10^{-2}) 	imes L = 75 	imes 10^{-4}$$L = \frac{75 	imes 10^{-4}}{12 	imes 10^{-2}}$$L = 6.25 	imes 10^{-2} \ m$Thus,the internal circumference of the capillary is $6.25 	imes 10^{-2} \ m$.

Water rises in a capillary tube to a height such that the upward force of surface tension balances the downward force of $75 \times 10^{-4} \ N$ due to the weight of the water. If the surface tension of water is $12 \times 10^{-2} \ N/m$,the internal circumference of the capillary must be:

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