Verify whether the following are True or False:

$-\frac{1}{3}$ is a zero of $3 x+1$

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A zero of a polynomial $p ( x )$ is a number $c$ such that $p ( c )=0$

Let $p(x)=3 x+1$

$\therefore \quad p\left(-\frac{1}{3}\right)=3\left(-\frac{1}{3}\right)+1=-1+1=0$

Hence, $-\frac{1}{3}$ is zero of $p ( x )=3 x +1$

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