Values of dissociation constant,K_a are given | vedclass

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(C) The strength of an acid is directly proportional to its dissociation constant $K_a$. Given $K_a$ values: $HCN$ $(6.2 	imes 10^{-10})$,$HNO_2$ $(4

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$F^{-} < NO_2^- < CN^{-}$

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(C) The strength of an acid is directly proportional to its dissociation constant $K_a$. Given $K_a$ values: $HCN$ $(6.2 	imes 10^{-10})$,$HNO_2$ $(4.0 	imes 10^{-4})$,$HF$ $(7.2 	imes 10^{-4})$. Thus,the order of acidic strength is $HCN Since the conjugate base of a stronger acid is a weaker base,the order of base strength is the inverse of the acidic strength. Therefore,the order of increasing base strength is $F^{-} < NO_2^- < CN^{-}$.

Values of dissociation constant,$K_a$ are given as follows:
Acid $K_a$
$HCN$ $6.2 \times 10^{-10}$
$HF$ $7.2 \times 10^{-4}$
$HNO_2$ $4.0 \times 10^{-4}$

Correct order of increasing base strength of the bases $CN^{-}$,$F^{-}$ and $NO_2^-$ will be:

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Acid	$K_a$
$HCN$	$6.2 \times 10^{-10}$
$HF$	$7.2 \times 10^{-4}$
$HNO_2$	$4.0 \times 10^{-4}$

Values of dissociation constant,$K_a$ are given as follows:Acid$K_a$$HCN$$6.2 \times 10^{-10}$$HF$$7.2 \times 10^{-4}$$HNO_2$$4.0 \times 10^{-4}$Correct order of increasing base strength of the bases $CN^{-}$,$F^{-}$ and $NO_2^-$ will be: