Two waves represented by the following equati | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The intensity $I$ of a wave is directly proportional to the square of its amplitude $a$ $(I \propto a^2)$.Given the wave equations:$y_1 = 5\sin 2\

Vedclass · Accepted Answer

$1:4$

Vedclass · Answer

(B) The intensity $I$ of a wave is directly proportional to the square of its amplitude $a$ $(I \propto a^2)$.Given the wave equations:$y_1 = 5\sin 2\pi (75t - 0.25x) \implies a_1 = 5$$y_2 = 10\sin 2\pi (150t - 0.50x) \implies a_2 = 10$The ratio of intensities is given by $\frac{I_1}{I_2} = \frac{a_1^2}{a_2^2}$.Substituting the values: $\frac{I_1}{I_2} = \frac{5^2}{10^2} = \frac{25}{100} = \frac{1}{4}$.Thus,the intensity ratio is $1:4$.

Two waves represented by the following equations are travelling in the same medium: $y_1 = 5\sin 2\pi (75t - 0.25x)$ and $y_2 = 10\sin 2\pi (150t - 0.50x)$. The intensity ratio $I_1/I_2$ of the two waves is:

Similar Questions

$A$ point source emits sound equally in all directions in a non-absorbing medium. Two points $P$ and $Q$ are at a distance of $9 \ m$ and $25 \ m$ respectively from the source. The ratio of the amplitudes of the waves at $P$ and $Q$ is

The intensity of sound from a radio at a distance of $2 \ m$ from its speaker is $1 \times 10^{-2} \ \mu W/m^2$. The intensity at a distance of $10 \ m$ would be:

If the ratio of the amplitude of two waves is $4 : 3$,then the ratio of their maximum and minimum intensity will be:

If the ratio of the amplitude of two waves is $4:3$,then the ratio of their maximum and minimum intensity is:

As a wave propagates:

Vedclass Test Series

Exam Paper Generator

Online Exam Module