If the ratio of the amplitude of two waves is $4:3$,then the ratio of their maximum and minimum intensity is:

The intensity of sound from a radio at a distance of $2 \ m$ from its speaker is $1 \times 10^{-2} \ \mu W/m^2$. The intensity at a distance of $10 \ m$ would be:

Statement-$1$: Two longitudinal waves given by equations $y_1(x, t) = 2a \sin(\omega t - kx)$ and $y_2(x, t) = a \sin(2\omega t - 2kx)$ will have equal intensity.
Statement-$2$: Intensity of waves of given frequency in the same medium is proportional to the square of amplitude only.

If the ratio of intensities of two waves is $1 : 25$,then the ratio of their amplitudes will be

$A$ spherical source of power $4 W$ and frequency $800 Hz$ is emitting sound waves. The intensity of waves at a distance $200 m$ is

$A$ stationary point source of sound emits sound uniformly in all directions in a non-absorbing medium. Two points $P$ and $Q$ are at a distance of $4 \ m$ and $9 \ m$ respectively from the source. The ratio of amplitudes of the waves at $P$ and $Q$ is