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(C) Let the time taken by the slower train to cross the faster train be $t$ seconds.Since the trains are moving in opposite directions,their relative

Vedclass · Accepted Answer

$48$

Vedclass · Answer

(C) Let the time taken by the slower train to cross the faster train be $t$ seconds.Since the trains are moving in opposite directions,their relative speed is the sum of their individual speeds:Relative speed $= 60 + 90 = 150 \; km/hr$.The total distance to be covered to cross each other is the sum of their lengths:Total length $= 1.1 + 0.9 = 2 \; km$.Time taken to cross each other is given by $t = \frac{	ext{Total length}}{	ext{Relative speed}}$.$t = \frac{2 \; km}{150 \; km/hr} = \frac{1}{75} \; hours$.To convert the time into seconds,multiply by $3600$:$t = \frac{1}{75} 	imes 3600 \; seconds = 48 \; seconds$.

Two trains are moving in opposite directions at $60 \; km/hr$ and $90 \; km/hr$ respectively. Their lengths are $1.1 \; km$ and $0.9 \; km$ respectively. The time taken by the slower train to cross the faster train in seconds is

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