$A$ $270 \;m$ long train running at a speed of $120 \;km/hr$ crosses another train running in the opposite direction at a speed of $80 \;km/hr$ in $9 \;seconds$. What is the length (in $m$) of the other train?

Length of a train and that of a platform are equal. If with a speed of $135 \; km/hr$,the train crosses the platform in $40 \; seconds$,then the length (in $m$) of the train is:

$A$ train speeds past a pole in $15 \; \text{seconds}$ and a platform $100 \; \text{m}$ long in $25 \; \text{seconds}$. Its length is (in $\text{m}$):

Two trains are moving in opposite directions at $60 \; km/hr$ and $90 \; km/hr$ respectively. Their lengths are $1.1 \; km$ and $0.9 \; km$ respectively. The time taken by the slower train to cross the faster train in seconds is

$A$ train covers a distance between two stations $A$ and $B$ in $45$ minutes. If the speed is reduced by $5 \; km/h$,it will cover the same distance in $48$ minutes. What is the distance between the two stations $A$ and $B$ (in $km$)? Also,find the speed of the train.

$A$ train passes a station platform in $36 \; \text{seconds}$ and a man standing on the platform in $20 \; \text{seconds}$. If the speed of the train is $54 \; \text{km/hr}$, what is the length (in $m$) of the platform?