A 300 ;m long train crosses a platform in 39 | vedclass

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Question

(B) Let the length of the platform be $x \;m$.When the train crosses a signal pole,it covers its own length. Therefore,the speed of the train is:$	ex

Vedclass · Accepted Answer

$350$

Vedclass · Answer

(B) Let the length of the platform be $x \;m$.When the train crosses a signal pole,it covers its own length. Therefore,the speed of the train is:$	ext{Speed} = \frac{	ext{Distance}}{	ext{Time}} = \frac{300 \;m}{18 \;s} = \frac{50}{3} \;m/s$.When the train crosses a platform,it covers the sum of its own length and the length of the platform. Therefore:$	ext{Speed} = \frac{300 + x}{39} \;m/s$.Equating the two expressions for speed:$\frac{300 + x}{39} = \frac{50}{3}$.Multiplying both sides by $39$:$300 + x = \frac{50}{3} 	imes 39$.$300 + x = 50 	imes 13$.$300 + x = 650$.$x = 650 - 300 = 350 \;m$.Thus,the length of the platform is $350 \;m$.

$A$ $300 \;m$ long train crosses a platform in $39 \;seconds$,while it crosses a signal pole in $18 \;seconds$. What is the length of the platform? (In $m$)

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