Two thin dielectric slabs of dielectric constants $K_1$ and $K_2$ $(K_1 < K_2)$ are inserted between the plates of a parallel plate capacitor,as shown in the figure. The variation of the electric field $E$ between the plates with distance $d$ as measured from plate $P$ is correctly shown by:

In the given circuit,$C_1=2\,\mu F, C_2=0.2\,\mu F, C_3=2\,\mu F, C_4=4\,\mu F, C_5=2\,\mu F, C_6=2\,\mu F$. The charge stored on capacitor $C_4$ is $.....\mu C$.

Seven capacitors,each of capacitance $2\ \mu F$,are connected in such a way that the total equivalent capacitance is $\frac{10}{11}\ \mu F$. Which of the following circuit diagrams represents this arrangement?

The figure shows two identical parallel plate capacitors $A$ and $B$ of capacitances $C$ connected to a battery. The key $K$ is initially closed. The switch is now opened and the free spaces between the plates of the capacitors are filled with a dielectric of dielectric constant $K=3$. Then which of the following statement$(s)$ is/are true?

The material filled between the plates of a parallel plate capacitor has resistivity $200 \, \Omega \, m$. The capacitance of the capacitor is $2 \, pF$. If a potential difference of $40 \, V$ is applied across the plates,the leakage current flowing through the capacitor is (given the relative permittivity of the material is $50$):

Each plate of a parallel plate capacitor has a charge $q$ on it. The capacitor is now connected to a battery. Now,