Two students,Anil and Ashima,appeared in an e | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Let $E$ and $F$ denote the events that Anil and Ashima will qualify the examination,respectively.Given that $P(E) = 0.05$,$P(F) = 0.10$,and $P(E \

Vedclass · Accepted Answer

$0.11$

Vedclass · Answer

(A) Let $E$ and $F$ denote the events that Anil and Ashima will qualify the examination,respectively.Given that $P(E) = 0.05$,$P(F) = 0.10$,and $P(E \cap F) = 0.02$.The event that only one of them will qualify the examination is given by $(E \cap F') \cup (E' \cap F)$,where $E'$ and $F'$ are the complements of $E$ and $F$ respectively.Since these events are mutually exclusive,the probability is:$P(	ext{only one}) = P(E \cap F') + P(E' \cap F)$$= [P(E) - P(E \cap F)] + [P(F) - P(E \cap F)]$$= (0.05 - 0.02) + (0.10 - 0.02)$$= 0.03 + 0.08 = 0.11$.

Similar Questions

Check whether the following probabilities $P(A)$ and $P(B)$ are consistently defined: $P(A) = 0.5$,$P(B) = 0.7$,$P(A \cap B) = 0.6$.

Let $A, B$ and $C$ be three events associated with sample space $S$. $A, B$ and $C$ are pairwise independent and $P(A)=P(B)=P(C)=P$. If all of them cannot occur simultaneously,then $P(A \cup B \cup C)$ is equal to

When two dice are thrown,the probability of getting an ordered pair $(x, y)$ such that $x^2+y^2 \leq 25$,where $x$ and $y$ are the numbers that show up on the two dice,is:

Let $S$ be the set of all quadratic equations of the form $x^2+bx+c=0$,where $b, c \in \{1, 2, 3, 4, 5, 6\}$. If an equation is selected at random from $S$,then the probability that the equation has real roots is

An experiment consists of recording the boy-girl composition of families with $2$ children. What is the sample space if we are interested in knowing whether it is a boy or girl in the order of their births?

Vedclass Test Series

Exam Paper Generator

Online Exam Module