Two spherical conductors A and B of radii 1 m | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

After connection, $V_{1}=V_{2}$

$\Rightarrow K \frac{Q_{1}}{r_1}=K \frac{Q_{2}}{r_{2}}$

$\Rightarrow \frac{Q_{1}}{r_{1}}=\frac{Q_{2}}{r_{2}}$

Vedclass · Accepted Answer

$2:1$

Vedclass · Answer

After connection, $V_{1}=V_{2}$

$\Rightarrow K \frac{Q_{1}}{r_1}=K \frac{Q_{2}}{r_{2}}$

$\Rightarrow \frac{Q_{1}}{r_{1}}=\frac{Q_{2}}{r_{2}}$

The ratio of electric fields

$\frac{E_{1}}{E_{2}}=\frac{K \frac{Q_{1}}{r_{1}^{2}}}{K \frac{Q_{2}}{r_{2}^{2}}}=\frac{Q_{1}}{r_1^{2}} 	imes \frac{r_{2}^{2}}{Q_{2}}$

$\Rightarrow \frac{E_{1}}{E_{2}}=\frac{r_{1} 	imes r_{2}^{2}}{r_1^{2} 	imes r_{2}}$

$ \Rightarrow \frac{E_{1}}{E_{2}}=\frac{r_{2}}{r_{1}}=\frac{2}{1}$

since the distance between the spheres is large as compared to their diameters, the induced effects may be ignored.

Similar Questions

A conducting sphere of radius $r$ has a charge. Then

Two metal spheres, one of radius $R$ and the other of radius $2R$, both have same surface charge density $\sigma $. They are brought in contact and separated. What will be new surface charge densities on them ?

A solid spherical conducting shell has inner radius a and outer radius $2a$. At the center of the shell is located a point charge $+Q$. What must the excess charge of the shell be in order for the charge density on the inner and outer surfaces of the shell to be exactly equal ?

Obtain the relation between electric field and electric potential.