Two projectiles are thrown simultaneously in | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The time of flight for a projectile is given by $T = \frac{2v \sin 	heta}{g}$. Since $v_1 \sin 	heta_1 = v_2 \sin 	heta_2$,it follows that $T_1

Vedclass · Accepted Answer

None of these.

Vedclass · Answer

(D) The time of flight for a projectile is given by $T = \frac{2v \sin 	heta}{g}$. Since $v_1 \sin 	heta_1 = v_2 \sin 	heta_2$,it follows that $T_1 = T_2$. Thus,option $A$ is correct.The maximum height is given by $H = \frac{v^2 \sin^2 	heta}{2g}$. Since $v_1 \sin 	heta_1 = v_2 \sin 	heta_2$,it follows that $H_1 = H_2$. Thus,option $B$ is correct.The relative acceleration between the two projectiles is $\vec{a}_{rel} = \vec{g} - \vec{g} = 0$. Since the relative acceleration is zero,the relative velocity $\vec{v}_{rel}$ remains constant. The relative vertical velocity is $v_{1y} - v_{2y} = v_1 \sin 	heta_1 - v_2 \sin 	heta_2 = 0$. Since the relative vertical velocity is zero,the relative motion is purely horizontal. Thus,the trajectory of one with respect to the other is a horizontal straight line. Option $C$ is correct.Since all statements $A$,$B$,and $C$ are correct,the incorrect statement is none of these.

Two projectiles are thrown simultaneously in the same plane from the same point. If their velocities are $v_1$ and $v_2$ at angles $\theta_1$ and $\theta_2$ respectively from the horizontal,and $v_1 \sin \theta_1 = v_2 \sin \theta_2$,then choose the incorrect statement.

Similar Questions

$A$ projectile is thrown into air with velocity $15 \ m/s$ at an angle $30^{\circ}$ with the horizontal. After what time is its direction of motion perpendicular to its initial direction (in $s$)? (Assume $g = 10 \ m/s^2$)

Two balls are thrown as shown in the figure and they reach the ground in the same time. What is the ratio of the maximum heights attained by them?

$A$ projectile crosses two walls of equal height $H$ symmetrically as shown. The height of each wall is ........ $m$.

Four persons $K, L, M$ and $N$ are initially at the corners of a square of side length $d$. If every person starts moving with speed $v$ such that $K$ is always headed towards $L$,$L$ towards $M$,$M$ towards $N$,and $N$ towards $K$,then the four persons will meet after

$A$ person moves from $A$ to $B$ on a circular path as shown in the figure. If the distance travelled by him is $60 \, m$,then the magnitude of the displacement would be $..... \, m$. (Given $\cos 135^{\circ} = -0.7$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module