Two masses $M$ and $m$ are attached to a vertical axis by weightless threads of combined length $l$. They are set in rotational motion in a horizontal plane about this axis with constant angular velocity $\omega $. If the tensions in the threads are the same during motion, the distance of $M$ from the axis is
$\frac{{Ml}}{{M + m}}$
$\frac{{ml}}{{M + m}}$
$\frac{{M + m}}{M}l$
$\frac{{M + m}}{m}l$
Find the centre of mass of three particles at the vertices of an equilateral triangle. The masses of the particles are $100\; g , 150 \;g ,$ and $200\; g$ respectively. Each side of the equilateral triangle is $0.5\; m$ long.
$A$ point mass $m_A$ is connected to a point mass $m_B$ by a massless rod of length $l$ as shown in the figure. It is observed that the ratio of the moment of inertia of the system about the two axes $BB$ and $AA$, which is parallel to each other and perpendicular to the rod is $\frac{{{I_{BB}}}}{{{I_{AA}}}}=3$. The distance of the centre of mass of the system from the mass $A$ is
A $T$ shaped object with dimensions shown in the figure, is lying a smooth floor. A force $'\vec F'$ is applied at the point $P$ parallel to $AB,$ such that the object has only the translational motion without rotation. Find the location of $P$ with respect to $C$
From a uniform square plate, one-fourth part is removed as shown. The centre of mass of remaining part will lie on
In the figure shown $ABC$ is a uniform wire . If centre of mass of wire lies vertically below point $A$ , then $\frac{{BC}}{{AB}}$ is close to