Two ions of masses 4 ,{amu} and 16, amu have | vedclass

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Question

${r}=\frac{{P}}{{qB}}=\frac{\sqrt{2 {mk}}}{{qB}}$

Given they have same kinetic energy

${r} \propto \frac{\sqrt{{m}}}{{q}}$

$\frac{{r}_{1}}{{T

Vedclass · Accepted Answer

lighter ion will be deflected more than heavier ion

Vedclass · Answer

${r}=\frac{{P}}{{qB}}=\frac{\sqrt{2 {mk}}}{{qB}}$

Given they have same kinetic energy

${r} \propto \frac{\sqrt{{m}}}{{q}}$

$\frac{{r}_{1}}{{T}_{2}}=\frac{\sqrt{4}}{2} 	imes \frac{3}{\sqrt{16}}=\frac{3}{4}$

${I}_{2}=\frac{4 {r}_{1}}{3}\left[{r}_{2}ight.$ is for hearier ion and ${r}_{1}$ is for lighter ion)

$\sin 	heta=\frac{{d}}{{R}}$

$	heta ightarrow$ Deflection

$	heta \propto \frac{1}{{R}}$

$({R} ightarrow$ Radius of path)

$\because {R}_{2}>{R}_{1} \Rightarrow 	heta_{2}<	heta_{1}$

Two ions of masses $4 \,{amu}$ and $16\, amu$ have charges $+2 {e}$ and $+3 {e}$ respectively. These ions pass through the region of constant perpendicular magnetic field. The kinetic energy of both ions is same. Then :

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