In toroid magnetic field on axis will be the | vedclass

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Question

The expression for toroid magnetic field is given by

$B=\mu_{0} \mu_{r}\left[\frac{N}{2 \pi r}ight] I$ $......(I)$

Substitute $4 \pi 	imes 10

Vedclass · Accepted Answer

$10.5$

Vedclass · Answer

The expression for toroid magnetic field is given by

$B=\mu_{0} \mu_{r}\left[\frac{N}{2 \pi r}ight] I$ $......(I)$

Substitute $4 \pi 	imes 10^{-7}$ for $\mu_{o}, 700$ for $\mu_{r}, 250 	imes 100$ for $N 0.5$ for $r$ and $1.5$ for $I$ in equation $(I).$

$B=\left(4 \pi 	imes 10^{-7}ight)(700)\left[\frac{250 	imes 100}{2 \pi(0.5)}ight](1.5)$

$=\frac{1400 	imes 10^{-7} 	imes 25 	imes 10^{3} 	imes 1.5}{0.5}$

$=75 	imes 1400 	imes 10^{-1}$ Tesla

$=10.5$ Tesla

In toroid magnetic field on axis will be the radius $=0.5\, cm ,$ current $=1.5\, A ,$ turns $=250,$ permeability $=700$ (in Tesla)

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