Two identical satellites $A$ and $B$ are orbiting the Earth at heights of $R$ and $2R$ respectively,where $R$ is the radius of the Earth. The ratio of the kinetic energy of $A$ to that of $B$ is:

The energy required to take a satellite to a height $h$ above the Earth's surface (radius of Earth $R = 6.4 \times 10^3 \, km$) is $E_1$,and the kinetic energy required for the satellite to be in a circular orbit at this height is $E_2$. The value of $h$ for which $E_1 = E_2$ is:

Let the kinetic energy of a satellite be $x$,then its time of revolution $T$ is proportional to ..............

If the time period of revolution of a satellite is $T$,then its kinetic energy is proportional to

In a satellite,if the time of revolution is $T$,then the kinetic energy $(K.E.)$ is proportional to:

$A$ satellite of mass $m$ is orbiting the Earth (of radius $R$) at a height equal to the radius of the Earth. The total energy of the satellite in terms of $g$ (acceleration due to gravity on Earth's surface) is