Two identical capacitors $A$ and $B$,charged to the same potential $V$,are connected in two different circuits as shown below at time $t=0$. If the charge on capacitors $A$ and $B$ at time $t=CR$ is $Q_{A}$ and $Q_{B}$ respectively,then (Here $e$ is the base of natural logarithm):

• A
  $Q_{A}=VC, Q_{B}=\frac{VC}{e}$
• B
  $Q_{A}=\frac{CV}{2}, Q_{B}=\frac{VC}{e}$
• C
  $Q_{A}=VC, Q_{B}=CV$
• D
  $Q_{A}=\frac{VC}{e}, Q_{B}=\frac{CV}{2}$