Two identical capacitors $1$ and $2$ are connected in series. The capacitor $2$ contains a dielectric slab of constant $K$ as shown. They are connected to a battery of emf $V_0\ volts$ . The dielectric slab is then removed. Let $Q_1$ and $Q_2$ be the charge stored in the capacitors before removing the slab and $Q'_1$ , and $Q'_2$ be the values after removing the slab. Then
Two identical capacitors $1$ and $2$ are connected in series. The capacitor $2$ contains a dielectric slab of constant $K$ as shown. They are connected to a battery of emf $V_0\ volts$ . The dielectric slab is then removed. Let $Q_1$ and $Q_2$ be the charge stored in the capacitors before removing the slab and $Q'_1$ , and $Q'_2$ be the values after removing the slab. Then
- A
$\frac{{Q{'_1}}}{{{Q_1}}} = \left( {\frac{{K + 1}}{K}} \right)$
- B
$\frac{{Q{'_2}}}{{{Q_2}}} = \frac{{\left( {K + 1} \right)}}{2}$
- C
$\frac{{Q{'_2}}}{{{Q_2}}} = \frac{{K + 1}}{{2K}}$
- D
$\frac{{Q{'_1}}}{{{Q_1}}} = \frac{K}{2}$
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