(C) The capacitance of a parallel plate capacitor is given by $C = \frac{K \epsilon_0 A}{d}$,where $K$ is the dielectric constant,$A$ is the area,and

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(C) The capacitance of a parallel plate capacitor is given by $C = \frac{K \epsilon_0 A}{d}$,where $K$ is the dielectric constant,$A$ is the area,and $d$ is the distance between the plates.Given that the new distance $d' = \frac{d}{2}$ and the new dielectric constant $K' = 3K$.The new capacitance $C'$ becomes $C' = \frac{(3K) \epsilon_0 A}{(d/2)} = 6 \left( \frac{K \epsilon_0 A}{d} \right) = 6C$.Thus,the Assertion is correct.The capacity of a capacitor depends on the dielectric constant $(K)$ of the material placed between the plates. Therefore,the Reason is incorrect.

Class 12 Physics Electric Potential and Capacitance Effect of Dielectric Inside Capacitor

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Assertion : If the distance between parallel plates of a capacitor is halved and the dielectric constant is increased to three times its original value,then the capacitance becomes $6$ times.
Reason : The capacity of a capacitor does not depend upon the nature of the material between the plates.

AIIMS 1997 All AIIMS

A
If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.
B
If both Assertion and Reason are correct but Reason is not a correct explanation of the Assertion.
C
If the Assertion is correct but Reason is incorrect.
D
If both the Assertion and Reason are incorrect.

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Class 12

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Electric Potential and Capacitance

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Effect of Dielectric Inside Capacitor

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AIIMS 1997 Paper All AIIMS years →

$A$ capacitor is half-filled with a dielectric $(K=2)$ as shown in Figure $A$. If the same capacitor is to be filled with the same dielectric as shown in Figure $B$, what would be the thickness $t$ of the dielectric so that the capacitor still has the same capacity?

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$A$ parallel plate capacitor has two layers of dielectric as shown in the figure. This capacitor is connected across a battery. The graph between electric field $(E)$ and distance $(x)$ from the left plate will be:

Medium

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$A$ slab of material of dielectric constant $K$ has the same area as the plates of a parallel-plate capacitor but has a thickness $(3/4)d$,where $d$ is the separation of the plates. How is the capacitance changed when the slab is inserted between the plates?

Medium

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In the given figure,there are two capacitors in series. $A$ rigid conducting slab of thickness $b$ can slide vertically. Find the equivalent capacitance of the system.

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The distance between the plates of a parallel plate capacitor is $d$. $A$ metal plate of thickness $d/2$ is introduced between the plates. The capacitance will then be

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Assertion : If the distance between parallel plates of a capacitor is halved and the dielectric constant is increased to three times its original value,then the capacitance becomes $6$ times.Reason : The capacity of a capacitor does not depend upon the nature of the material between the plates.

Similar Questions

$A$ capacitor is half-filled with a dielectric $(K=2)$ as shown in Figure $A$. If the same capacitor is to be filled with the same dielectric as shown in Figure $B$, what would be the thickness $t$ of the dielectric so that the capacitor still has the same capacity?

$A$ parallel plate capacitor has two layers of dielectric as shown in the figure. This capacitor is connected across a battery. The graph between electric field $(E)$ and distance $(x)$ from the left plate will be:

$A$ slab of material of dielectric constant $K$ has the same area as the plates of a parallel-plate capacitor but has a thickness $(3/4)d$,where $d$ is the separation of the plates. How is the capacitance changed when the slab is inserted between the plates?

In the given figure,there are two capacitors in series. $A$ rigid conducting slab of thickness $b$ can slide vertically. Find the equivalent capacitance of the system.

The distance between the plates of a parallel plate capacitor is $d$. $A$ metal plate of thickness $d/2$ is introduced between the plates. The capacitance will then be

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Assertion : If the distance between parallel plates of a capacitor is halved and the dielectric constant is increased to three times its original value,then the capacitance becomes $6$ times.
Reason : The capacity of a capacitor does not depend upon the nature of the material between the plates.