Two homo-diatomic molecules $X_2$ and $Y_2$ have the same bond order. Then,select the $CORRECT$ statement.
- ABoth must have the same number of total antibonding electrons.
- BBoth must have the same number of total bonding electrons.
- CThe difference between the total number of antibonding electrons and bonding electrons must be the same for both molecules.
- DBoth $(A)$ and $(B)$ are correct.
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Similar Questions
Which of the following combinations leads to the $HOMO$ of the $N_2$ molecule?
Medium
View SolutionConsider the following changes $I$ and $II$ as shown in the figure. The correct statements about these changes $(I)$ and $(II)$ in accordance with $MO$ theory are:
$A$) In $(I)$ bond order increases by $0.5$ from the existing value.
$B$) In $(II)$ bond order decreases by $0.5$ from the existing value.
$C$) In both $(I)$ and $(II)$ magnetic property is changed.
$D$) In both $(I)$ and $(II)$ magnetic property is not changed.
$A$) In $(I)$ bond order increases by $0.5$ from the existing value.
$B$) In $(II)$ bond order decreases by $0.5$ from the existing value.
$C$) In both $(I)$ and $(II)$ magnetic property is changed.
$D$) In both $(I)$ and $(II)$ magnetic property is not changed.
Which of the following molecular orbitals has the maximum number of nodal planes?
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View SolutionThe bond order of $HeH^{+}$ is
Which of the following species has the highest bond order?
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