Two homo-diatomic molecules $'X'_2$ and $'Y'_2$ have same bond order then select the CORRECT statement
Two homo-diatomic molecules $'X'_2$ and $'Y'_2$ have same bond order then select the CORRECT statement
- A
Both must have same number of total antibonding electrons
- B
Both must have same number of total bonding electrons
- C
Difference of total number of antibonding electron and bonding electron must be same for both molecules
- D
Both $(A)$ and $(B)$
Similar Questions
Choose correct order
Choose correct order
Match each of the diatomic molecules in Column $I$ with its property / properties in Column $II$.
Column $I$
Column $II$
$(A)$ $\mathrm{B}_2$
$(p)$ Paramagnetic
$(B)$ $\mathrm{N}_2$
$(q)$ Undergoes oxidation
$(C)$ $\mathrm{O}_2^{-}$
$(r)$ Undergoes reduction
$(D)$ $\mathrm{O}_2$
$(s)$ Bond order $\geq 2$
$(t)$ Mixing of ' $\mathrm{s}$ ' and ' $\mathrm{p}$ ' orbitals
Match each of the diatomic molecules in Column $I$ with its property / properties in Column $II$.
| Column $I$ | Column $II$ |
| $(A)$ $\mathrm{B}_2$ | $(p)$ Paramagnetic |
| $(B)$ $\mathrm{N}_2$ | $(q)$ Undergoes oxidation |
| $(C)$ $\mathrm{O}_2^{-}$ | $(r)$ Undergoes reduction |
| $(D)$ $\mathrm{O}_2$ | $(s)$ Bond order $\geq 2$ |
| $(t)$ Mixing of ' $\mathrm{s}$ ' and ' $\mathrm{p}$ ' orbitals |
- [IIT 2009]
Bond order of $C_2$ vapour is :
Bond order of $C_2$ vapour is :
Which of the following diatomic molecular species has only $\pi$ bonds according to Molecular Orbital Theory?
Which of the following diatomic molecular species has only $\pi$ bonds according to Molecular Orbital Theory?
- [NEET 2019]
A simplified application of $MO$ theory to the hypothitical molecule $'OF'$ would give its bond order as :-
A simplified application of $MO$ theory to the hypothitical molecule $'OF'$ would give its bond order as :-