Bond order of $C_2$ vapour is :
$\frac{8-4}{2} = 2$
$\frac{6-2}{2} = 2$
$\frac{8-2}{2} = 3$
$\frac{10-2}{2} = 4$
The molecular electronic configuration of $H_2^ - $ ion is
What is the effect of the following processes on the bond order in $\mathrm{N}_{2}$ and $\mathrm{O}_{2}$ ?
$(A)$ ${{\rm{N}}_2} \to {\rm{N}}_2^ + + {{\rm{e}}^ - }$
$(B)$ ${{\rm{O}}_2} \to {\rm{O}}_2^ + + {{\rm{e}}^ - }$
Give energy level diagram obtained by over lapping of $2{{\rm{p}}_{\rm{z}}}$ orbitals.And give a diagram of the orbits of that composition.
Which of the configuration is correct :-
${{\rm{H}}{{\rm{e}}_2}}$ molecule is not possible.