Match each of the diatomic molecules in Colum | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) $B_2$: $\sigma 1s^2 \sigma^{\star} 1s^2 \sigma 2s^2 \sigma^{\star} 2s^2 \pi 2p_y^1 \pi 2p_z^1$. It is paramagnetic. Bond order $= (6-4)/2 = 1$. Mi

Vedclass · Accepted Answer

$(A)$ $\rightarrow p, q, r \& \ t, (B)$ $\rightarrow q, r, s \& \ t, (C)$ $\rightarrow p, q, r, (D)$ $\rightarrow p, q, r \& \ s$

Vedclass · Answer

(A) $B_2$: $\sigma 1s^2 \sigma^{\star} 1s^2 \sigma 2s^2 \sigma^{\star} 2s^2 \pi 2p_y^1 \pi 2p_z^1$. It is paramagnetic. Bond order $= (6-4)/2 = 1$. Mixing of $s$ and $p$ orbitals occurs. $B_2$ undergoes oxidation and reduction.$(B)$ $N_2$: $\sigma 1s^2 \sigma^{\star} 1s^2 \sigma 2s^2 \sigma^{\star} 2s^2 \sigma 2p_x^2 \pi 2p_y^2 \pi 2p_z^2$. It is diamagnetic. Bond order $= (10-4)/2 = 3$. Mixing of $s$ and $p$ orbitals occurs. $N_2$ undergoes oxidation and reduction.$(C)$ $O_2^{-}$: Paramagnetic with bond order $= 1.5$. $O_2^{-}$ undergoes oxidation and reduction.$(D)$ $O_2$: $\sigma 1s^2 \sigma^{\star} 1s^2 \sigma 2s^2 \sigma^{\star} 2s^2 \sigma 2p_x^2 \pi 2p_y^2 \pi 2p_z^2 \pi^{\star} 2p_y^1 \pi^{\star} 2p_z^1$. Paramagnetic with bond order $= 2$. $O_2$ undergoes oxidation and reduction.Correct mapping: $(A)$ $\rightarrow p, q, r, t; (B)$ $\rightarrow q, r, s, t; (C)$ $\rightarrow p, q, r; (D)$ $\rightarrow p, q, r, s$.

Column $I$	Column $II$
$(A)$ $B_2$	$(p)$ Paramagnetic
$(B)$ $N_2$	$(q)$ Undergoes oxidation
$(C)$ $O_2^{-}$	$(r)$ Undergoes reduction
$(D)$ $O_2$	$(s)$ Bond order $\geq 2$
	$(t)$ Mixing of '$s$' and '$p$' orbitals

Pair of species	Identical property
$A$. $B_2 \& O_2$	$P$. Bond order $= 2.5$
$B$. $Be_2 \& H_2^{2-}$	$Q$. Paramagnetic nature
$C$. $N_2^{+} \& N_2^{-}$	$R$. Diamagnetic nature
$D$. $O_2^{+} \& O_2^{-}$	$S$. Doesn't exist

Similar Questions

What is the bond order of $O_2^-$ (in $.5$)?

The total number of molecular orbitals formed from $2s$ and $2p$ atomic orbitals of a diatomic molecule is:

Match the following:

Pair of species Identical property

$A$. $B_2 \& O_2$ $P$. Bond order $= 2.5$

$B$. $Be_2 \& H_2^{2-}$ $Q$. Paramagnetic nature

$C$. $N_2^{+} \& N_2^{-}$ $R$. Diamagnetic nature

$D$. $O_2^{+} \& O_2^{-}$ $S$. Doesn't exist

What is the bond order of the $Be_{2}$ molecule?

Which of the following molecules does not exist on the basis of Molecular Orbital Theory?

Vedclass Test Series

Exam Paper Generator

Online Exam Module