Two equal negative charges -q are fixed at th | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) By the symmetry of the problem,the components of the force on $Q$ due to the charges at $A$ and $B$ along the $Y$-axis will cancel each other,whil

Vedclass · Accepted Answer

Execute oscillatory but not simple harmonic motion

Vedclass · Answer

(D) By the symmetry of the problem,the components of the force on $Q$ due to the charges at $A$ and $B$ along the $Y$-axis will cancel each other,while the components along the $X$-axis will add up and be directed towards the origin $O$. Under the action of this force,the charge $Q$ will move towards $O$.If at any time the charge $Q$ is at a distance $x$ from $O$,the net force on charge $Q$ is:$F_{net} = 2F \cos 	heta = 2 \left( \frac{1}{4\pi \varepsilon_0} \frac{qQ}{a^2 + x^2} ight) \left( \frac{x}{\sqrt{a^2 + x^2}} ight)$$F_{net} = - \frac{1}{4\pi \varepsilon_0} \frac{2qQx}{(a^2 + x^2)^{3/2}}$Since the restoring force $F_{net}$ is not proportional to the displacement $x$ (it is not linear),the motion will be oscillatory (with an amplitude of $2a$) but not simple harmonic.

Two equal negative charges $-q$ are fixed at the points $(0, a)$ and $(0, -a)$ on the $Y$-axis. $A$ positive charge $Q$ is released from rest at the point $(2a, 0)$ on the $X$-axis. The charge $Q$ will:

Similar Questions

Six charges are placed at the corners of a regular hexagon as shown. If an electron is placed at its centre $O$,the force on it will be:

Two electric charges $+2 \mu C$ and $-4 \mu C$ are separated by a distance $3 \ m$ in air. At a point $P$ located on the line joining the two charges and in between them, the electric potential is zero. Then the electric field at point $P$ (in $NC^{-1}$) is (in $,000$)

The dimension of $\frac{1}{2} \varepsilon_0 E^2$,where $\varepsilon_0$ is the permittivity of free space and $E$ is the electric field,is:

An uncharged metal sphere is placed between two charged parallel plates. The pattern of the electric field lines will be:

Charges are placed on the vertices of a square as shown. Let $\vec E$ be the electric field and $V$ be the potential at the centre. If the charges on $A$ and $B$ are interchanged with those on $D$ and $C$ respectively,then

Vedclass Test Series

Exam Paper Generator

Online Exam Module