Two equal charges of magnitude $Q$ each are placed at a distance $d$ apart. Their electrostatic energy is $E$. A third charge $-Q / 2$ is brought midway between these two charges. The electrostatic energy of the system is now

  • [KVPY 2014]
  • A

    $-2 E$

  • B

    $-E$

  • C

    $0$

  • D

    $E$

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