Two dice are thrown together. The probability that at least one will show its digit $6$ is
$\frac{{11}}{{36}}$
$\frac{{36}}{{11}}$
$\frac{5}{{11}}$
$\frac{1}{6}$
The probability of a sure event is
Two players play the following game: $A$ writes $3,5,6$ on three different cards: $B$ writes $8,9,10$ on three different cards. Both draw randomly two cards from their collections. Then, $A$ computes the product of two numbers helshe has drawn, and $B$ computes the sum of two numbers he/she has drawn. The player getting the larger number wins. What is the probability that A wins?
Two dice are thrown and the sum of the numbers which come up on the dice is noted. Let us consider the following events associated with this experiment
$A:$ $^{\prime}$ the sum is even $^{\prime}$.
$B:$ $^{\prime}$the sum is a multiple of $3$$^{\prime}$
$C:$ $^{\prime}$the sum is less than $4 $$^{\prime}$
$D:$ $^{\prime}$the sum is greater than $11$$^{\prime}$.
Which pairs of these events are mutually exclusive ?
In a throw of a dice the probability of getting one in even number of throw is
A card is drawn randomly from a pack of playing cards. Then the probability that it is neither ace nor king, is