In a throw of a dice the probability of getti | vedclass

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Question

(b) Required probability

$=\left( {\frac{5}{6}} \right)\;\left( {\frac{1}{6}} \right)\; + \;{\left( {\frac{5}{6}} \right)^3}\left( {\frac{1}{6}} \r

Vedclass · Accepted Answer

$\frac{5}{{11}}$

Vedclass · Answer

(b) Required probability

$=\left( {\frac{5}{6}} \right)\;\left( {\frac{1}{6}} \right)\; + \;{\left( {\frac{5}{6}} \right)^3}\left( {\frac{1}{6}} \right) + \;{\left( {\frac{5}{6}} \right)^5}\left( {\frac{1}{6}} \right) + ...$

$= \frac{{\frac{5}{6}.\frac{1}{6}}}{{1 - {{\left( {\frac{5}{6}} \right)}^2}}} $

$= \frac{5}{{36 - 25}} = \frac{5}{{11}}$.

In a throw of a dice the probability of getting one in even number of throw is

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