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Question

(A) When two dice are thrown, the total number of possible outcomes is $6 	imes 6 = 36$.The condition 'sum is at least $10$' means the sum can be $10

Vedclass · Accepted Answer

$\frac{1}{6}$

Vedclass · Answer

(A) When two dice are thrown, the total number of possible outcomes is $6 	imes 6 = 36$.The condition 'sum is at least $10$' means the sum can be $10, 11,$ or $12$.Let us list the favorable outcomes for each sum:For sum $= 10$: $(4, 6), (5, 5), (6, 4)$ (Total $3$ outcomes)For sum $= 11$: $(5, 6), (6, 5)$ (Total $2$ outcomes)For sum $= 12$: $(6, 6)$ (Total $1$ outcome)Total number of favorable outcomes $= 3 + 2 + 1 = 6$.The probability is given by the ratio of favorable outcomes to total outcomes:$P(	ext{sum} \ge 10) = \frac{6}{36} = \frac{1}{6}$.

Two dice are thrown. Find the probability that the sum is at least $10$ ?

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