If A and B are two events such that A subsete | vedclass

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(B) Given that $A \subseteq B$. This implies that whenever event $A$ occurs,event $B$ must also occur. Therefore,the intersection of $A$ and $B$ is $A

Vedclass · Accepted Answer

$1$

Vedclass · Answer

(B) Given that $A \subseteq B$. This implies that whenever event $A$ occurs,event $B$ must also occur. Therefore,the intersection of $A$ and $B$ is $A \cap B = A$. By the definition of conditional probability,$P\left( \frac{B}{A} \right) = \frac{P(A \cap B)}{P(A)}$. Substituting $A \cap B = A$ into the formula,we get $P\left( \frac{B}{A} \right) = \frac{P(A)}{P(A)} = 1$ (provided $P(A) > 0$).

If $A$ and $B$ are two events such that $A \subseteq B,$ then $P\left( \frac{B}{A} \right) = $

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