If four persons are chosen at random from a group of $3$ men,$2$ women,and $4$ children,then the probability that exactly two of them are children is:

  • A
    $\frac{10}{21}$
  • B
    $\frac{8}{63}$
  • C
    $\frac{5}{21}$
  • D
    $\frac{9}{21}$

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