Two coaxial solenoids are made by winding thi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The formula for the mutual inductance $M$ of two coaxial solenoids is given by $M = \frac{\mu_0 N_1 N_2 A}{\ell}$.Given values are:$A = 10 \ cm^2

Vedclass · Accepted Answer

$2.4\pi 	imes 10^{-4} \ H$

Vedclass · Answer

(A) The formula for the mutual inductance $M$ of two coaxial solenoids is given by $M = \frac{\mu_0 N_1 N_2 A}{\ell}$.Given values are:$A = 10 \ cm^2 = 10 	imes 10^{-4} \ m^2 = 10^{-3} \ m^2$$\ell = 20 \ cm = 0.2 \ m$$N_1 = 300$$N_2 = 400$$\mu_0 = 4\pi 	imes 10^{-7} \ T \ m \ A^{-1}$Substituting these values into the formula:$M = \frac{(4\pi 	imes 10^{-7}) 	imes 300 	imes 400 	imes 10^{-3}}{0.2}$$M = \frac{4\pi 	imes 10^{-7} 	imes 120000 	imes 10^{-3}}{0.2}$$M = \frac{4\pi 	imes 10^{-7} 	imes 120}{0.2}$$M = 4\pi 	imes 10^{-7} 	imes 600$$M = 2400\pi 	imes 10^{-7} \ H = 2.4\pi 	imes 10^{-4} \ H$.

Similar Questions

The mutual inductance $(M)$ of two coils is $3 \ H$. The self-inductances of the coils are $4 \ H$ and $9 \ H$ respectively. The coefficient of coupling between the coils is

The mutual inductance of a system of two coils does not depend on . . . . . . .

In a transformer, the coefficient of mutual inductance between the primary and the secondary coil is $0.2 \, H$. When the current changes by $5 \, A/s$ in the primary, the induced $e.m.f.$ in the secondary will be......$V$

Vedclass Test Series

Exam Paper Generator

Online Exam Module