Two coaxial solenoids are made by winding thin insulated wire over a pipe of cross-sectional area $A = 10\ cm^2$ and length$= 20\ cm$. If one of the solenoid has $300$ turns and the other $400$ turns, their mutual inductance is
$\mu_{0}=4 \pi \times 10^{-7} \;TmA ^{-1}$
$2.4$$\pi $ $\times$ $10^{-4}$ $H$
$2.4$ $\pi $ $\times$ $10^{-5}$ $H$
$4.8$$\pi $ $\times 10^{-4}$ $H$
$4.8$ $\pi $ $\times$ $ 10^{-5} $ $H$
Two coils are placed close to each other. The mutual inductance of the pair of coils depends upon
The mutual inductance of a pair of coils, each of $N\,turns$, is $M\,henry$. If a current of $I\, ampere$ in one of the coils is brought to zero in $t$ $second$ , the $emf$ induced per turn in the other coil, in volt, will be
What is the coefficient of mutual inductance when the magnetic flux changes by $2 \times {10^{ - 2}}\,Wb$ and change in current is $0.01\,A$......$henry$
Two coil $A$ and $B$ have coefficient of mutual inductance $M = 2H$. The magnetic flux passing through coil $A$ changes by $4$ Weber in $10$ seconds due to the change in current in $B$. Then
Derive formula for mutual inductance for two very long coaxial solenoids. Also discuss reciprocity theorem.